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<title>PennyDellPuzzles.com - Let Us Know About Possible Mistakes (Dell) - May 2012 Logic Problem Dance Contest - Messages</title>
<link>http://www.pennydellpuzzles.com/forum/topic639-may-2012-logic-problem-dance-contest.aspx</link>
<description>PennyDellPuzzles.com - Let Us Know About Possible Mistakes (Dell) - May 2012 Logic Problem Dance Contest - Messages</description>
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<pubDate>Thu, 12 Apr 2012 11:42:20 GMT</pubDate>
<lastBuildDate>Thu, 12 Apr 2012 11:42:20 GMT</lastBuildDate>
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<link>http://www.pennydellpuzzles.com/forum/topic639-may-2012-logic-problem-dance-contest.aspx</link>
<title>Message from sullivande</title>
<description><![CDATA[Thank you, Frances.  You've been a great help; very articulate.  I was focused on the fact that five partners were being presented in clue 1; I overlooked the fact that four spouses were being presented, as well.]]></description>
<pubDate>Thu, 12 Apr 2012 11:42:20 GMT</pubDate>
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<link>http://www.pennydellpuzzles.com/forum/topic639-may-2012-logic-problem-dance-contest.aspx</link>
<title>Message from sullivande</title>
<description><![CDATA[<b>Frances</b> wrote:<br/><blockquote>Hi sullivande, <br/>I think the key to understanding this part of the logic is the fact that Jed and Barb are married. How do we know this? From Clue 1 we find all 5 couples: Neither Cyn, Jed, or their spouses danced together (4 couples) and none won the waltz. Using the diagram order of woman/partner/dance we get: <br/><br/>(1) Cyn <span style="color:#cc0000">SOMEBODY</span><span style="color:#000000">/---- ----/---- <br/>(2) ---- ----/Jed </span><span style="color:#0000ff">ANOTHERBODY</span><span style="color:#000000">/---- <br/>(3)---- ----/---- </span><span style="color:#cc0000">SOMEBODY</span><span style="color:#000000">/---- <br/>(4)---- </span><span style="color:#0000ff">ANOTHERBODY</span><span style="color:#000000">/---- ----/---- <br/>(5)---- ----/---- ----/Waltz <br/><br/>Now where can Barb winning the Charleston go? Not position 1 or 5. How about 2? No clue 7 says Charleston & Jed are 2 different. 3? No as clue 3 says Barb was with Deb's husband, not Cyn's and our chart tells us Cyn and postition 3 have same last name. That leaves position 4. Which means her last name is the same as Jed's. <br/><br/>According to Clue 6, if Jed DID dance with Ms. Karr, his surname (and Barb's) would be Larks. But according to Clue 7, Ms. Larks and Charleston were 2 different ones. So he didn't dance with Ms. Karr. Did I help or confuse you? <img src="images/smilies/smile.gif" border=0 alt="smile" /> <br/><br/>Frances.</span> <br/>edited by Frances on 4/11/2012</blockquote>]]></description>
<pubDate>Thu, 12 Apr 2012 11:35:31 GMT</pubDate>
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<link>http://www.pennydellpuzzles.com/forum/topic639-may-2012-logic-problem-dance-contest.aspx</link>
<title>Message from Frances</title>
<description><![CDATA[Hi sullivande, <br/>I think the key to understanding this part of the logic is the fact that Jed and Barb are married. How do we know this? From Clue 1 we find all 5 couples: Neither Cyn, Jed, or their spouses danced together (4 couples) and none won the waltz. Using the diagram order of woman/partner/dance we get: <br/><br/>(1) Cyn <span style="color:#cc0000">SOMEBODY</span><span style="color:#000000">/---- ----/---- <br/>(2) ---- ----/Jed </span><span style="color:#0000ff">ANOTHERBODY</span><span style="color:#000000">/---- <br/>(3)---- ----/---- </span><span style="color:#cc0000">SOMEBODY</span><span style="color:#000000">/---- <br/>(4)---- </span><span style="color:#0000ff">ANOTHERBODY</span><span style="color:#000000">/---- ----/---- <br/>(5)---- ----/---- ----/Waltz <br/><br/>Now where can Barb winning the Charleston go? Not position 1 or 5. How about 2? No clue 7 says Charleston & Jed are 2 different. 3? No as clue 3 says Barb was with Deb's husband, not Cyn's and our chart tells us Cyn and postition 3 have same last name. That leaves position 4. Which means her last name is the same as Jed's. <br/><br/>According to Clue 6, if Jed DID dance with Ms. Karr, his surname (and Barb's) would be Larks. But according to Clue 7, Ms. Larks and Charleston were 2 different ones. So he didn't dance with Ms. Karr. Did I help or confuse you? <img src="images/smilies/smile.gif" border=0 alt="smile" /> <br/><br/>Frances.</span><br/>&lt;em&gt;edited by Frances on 4/11/2012&lt;/em&gt;]]></description>
<pubDate>Wed, 11 Apr 2012 20:05:07 GMT</pubDate>
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<link>http://www.pennydellpuzzles.com/forum/topic639-may-2012-logic-problem-dance-contest.aspx</link>
<title>Message from sullivande</title>
<description><![CDATA[I couldn't figure this one out, so I went to the solution (Classic Variety Puzzles Plus Crosswords May 2012, page 116). I agree with the solution until: Jed's partner isn't Karr [Barb[Charleston] isn't Larks (7)] (6)<br/>I get that Barb isn't Larks because Larks and the winner of the Charleston are two different contestants (clue 7), but I don't see how clue 6 tells us that Jed's partner isn't Karr because Barb isn't Larks. Clue 6 tells us that Ms. Karr and Mr. Larks are partners. Am I missing the link between Jed's partner and his spouse, or is this faulty logic?]]></description>
<pubDate>Wed, 11 Apr 2012 16:28:46 GMT</pubDate>
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